Sed command for find and replace matched word from file

Just replace the word from access.log: We’ve one file called access.log with below mention data/line.

Replacing the “five-5-success-factor.html” with “replace.html”.

access.log:

Hello tutorialbyexample, home page access by GET http://www.tutorialbyexample.com/ success HTTP 200

This is the success page of five success by POST http://www.tutorialbyexample.com/2015/09/five-5-success-factor.html HTTP 200

Hello tutorialbyexample, home page access by GET http://www.tutorialbyexample.com/ success HTTP 200

This is the success page of five success by POST http://www.tutorialbyexample.com/2015/09/five-5-success-factor.html HTTP 200

Hello tutorialbyexample, home page access by GET http://www.tutorialbyexample.com/

This is the success page of five success by POST http://www.tutorialbyexample.com/2015/09/five-5-success-factor.html

Hello tutorialbyexample, home page access by GET http://www.tutorialbyexample.com/

Command:

sed -i 's/five-5-success-factor.html/replace.html/g' access_200.log

Output in same file access.log:

Hello tutorialbyexample, home page access by GET http://www.tutorialbyexample.com/ success HTTP 200

This is the success page of five success by POST http://www.tutorialbyexample.com/2015/09/replace.html HTTP 200

Hello tutorialbyexample, home page access by GET http://www.tutorialbyexample.com/ success HTTP 200

This is the success page of five success by POST http://www.tutorialbyexample.com/2015/09/replace.html HTTP 200

Hello tutorialbyexample, home page access by GET http://www.tutorialbyexample.com/

This is the success page of five success by POST http://www.tutorialbyexample.com/2015/09/replace.html

Hello tutorialbyexample, home page access by GET http://www.tutorialbyexample.com/